Concordis Posted December 8, 2011 Share Posted December 8, 2011 Am o problema pe care nu o stiu rezolva. Avem doi angajati care pleaca la munca. Primul face cu masina 2h24'. Celalalt ia autobuzul cu 24' inainte sa porneasca primul domnul si ajunge in 3h36. Cand il ajunge primul pe al doilea? In cat timp? Link to comment Share on other sites More sharing options...
sorin65 Posted December 8, 2011 Share Posted December 8, 2011 Am o problema pe care nu o stiu rezolva. Avem doi angajati care pleaca la munca. Primul face cu masina 2h24'. Celalalt ia autobuzul cu 24' inainte sa porneasca primul domnul si ajunge in 3h36. Cand il ajunge primul pe al doilea? In cat timp? 48 min Link to comment Share on other sites More sharing options...
Concordis Posted December 8, 2011 Author Share Posted December 8, 2011 48 min e corect dar eu am nevoie de metoda de rezolvare nu de rezultat Link to comment Share on other sites More sharing options...
Stimpson J. Cat Posted December 8, 2011 Share Posted December 8, 2011 (edited) di = distanta de intalnire df = distanta finala tf1 = timpul in care ajunge primul tf2 = timpul in care ajunge al doilea v1 = viteza primului v2 = viteza celui de-al doilea ti = timpul de intalnire Ne intereseaza ti-24 in final (adica ti). timp 1 -> 0 24 ti tf1 dist 1 -> 0 0 di df timp 2 -> 0 24 ti tf2 dist 2 -> 0 neint. di df Timpii 1 si 2 merg in paralel. Adica e interesant de urmarit distantele in paralel cu timpul. di = v1 * (ti-24) di = v2 * ti v1 = df / 2h24 v2 = df / 3h36 Inlocuim v1, v2 mai sus si egalam 'di'. Se reduce 'df' si iese o ecuatie de gradul 1 in 'ti'. Edited December 8, 2011 by Stimpson J. Cat Link to comment Share on other sites More sharing options...
sa fugim Posted December 12, 2011 Share Posted December 12, 2011 Sper ca domnii astia lucreaza pe ISS, altfel nu stiu ce job merita o naveta de 2-3 ore. Desi in economia asta... Link to comment Share on other sites More sharing options...
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